I have a killer headache trying to solve math problems. I'll give you 10 points for a right ans

Jimmy is a partner in an internet based coffee supplier company. The company offers gourmet coffee beans for $14 per pound and regular coffee beans for $5 per pound. Jimmy is creating a medium-price product that will sell for $7 per pound. The first thing to go into the mixing bin was 10 pounds of the groumet beans. How many pounds of the less expensive regular beans should be added.

an answer to this question would be great but I'd also like to learn how to do this, so if you can explain and give me any helpful hints on how to solve these it would be great. Thanks.

I have a killer headache trying to solve math problems. I'll give you 10 points for a right answer.?lyric opera

Hi,

Write the equation as:

gourmet cost per pound(pounds) + regular cost per pound(pounds) = mixture cost per pound(total pounds)

14(10) + 5(x) = 7(x + 10)

140 + 5x = 7x + 70

70 = 2x

35 = x

Add 35 pounds of the $5 per pound coffee.

A second interesting way to do this is to plot the costs on a number line.

..5....7...............14

--+----+--------------+--

The total difference in price of the 2 coffees is 14 - 5 or $9

The mixture is $2 more than the regular coffee and $7 less than the gourmet coffee. The mixture is 2/9 of the total difference in prices from the regular coffee and 7/9 of the total difference in prices from the gourmet coffee.

Now reverse these fractional amounts. That means that 7/9 of the coffee will be the $5 coffee and 2/9 of the mixture will be gourmet coffee. If 2/9 of the mixture is the added 10 pounds of gourmet coffee, then:

2/9x = 10

2x = 90

x = 45 This means the total mixture will have 45 pounds of coffees. Since 10 pounds were the gourmet beans, then 45 - 10 or 35 pounds were the regular-priced amount.

I hope that helps!! :-)

I have a killer headache trying to solve math problems. I'll give you 10 points for a right answer.?imax theater opera theater

I will use for gourmet coffee the notation "gc"

I will use for regular coffee the notation "rc"

we have "P" for the price and "M" for weight

Pgc will be the price for the gourmet coffee

Prc will be the price for the regular coffee

Mgc will be the weight of the gourmet coffee

Mrc will be the weight of the regular coffee

Pmp will be the price for the medium-pricecoffee

Mt total weight that goes in the mixing bin which is also = Mgc + Mrc

we have the following relation:

(Pgc x Mgc ) + (Prc x Mrc ) = Pmp x Mt

(Pgc x Mgc ) + (Prc x Mrc ) = Pmp x (Mgc + Mrc)

(Pgc x Mgc )-(PmpxMgc) = (PmpxMrc) -(PrcxMrc )

we regroup the terms:

(Pgc - Pmp)x Mgc = (Pmp - Prc) x Mrc

the only unknown is Mrc

Mrc = [(Pgc - Pmp)x Mgc]/(Pmp - Prc)

Pgc= 14$

Prc= 5$

Pmp = 7$

Mgc = 10 pounds

Mrc = ?

Mrc = [(14 - 7 )x 10]/(7 - 5) = 35 pounds should be added

Hope this helps and Good luck
(10*14 + x*5)/(10+x) = 7..... (total $)/(total lb) = 7$/lb

Solve for x

I got 35 lb